5n^2+39n-8=0

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Solution for 5n^2+39n-8=0 equation:



5n^2+39n-8=0
a = 5; b = 39; c = -8;
Δ = b2-4ac
Δ = 392-4·5·(-8)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1681}=41$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(39)-41}{2*5}=\frac{-80}{10} =-8 $
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(39)+41}{2*5}=\frac{2}{10} =1/5 $

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